4x^2+8x-400=0

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Solution for 4x^2+8x-400=0 equation:



4x^2+8x-400=0
a = 4; b = 8; c = -400;
Δ = b2-4ac
Δ = 82-4·4·(-400)
Δ = 6464
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{6464}=\sqrt{64*101}=\sqrt{64}*\sqrt{101}=8\sqrt{101}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8\sqrt{101}}{2*4}=\frac{-8-8\sqrt{101}}{8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8\sqrt{101}}{2*4}=\frac{-8+8\sqrt{101}}{8} $

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